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Mooc 课程：程序设计基础——发现计算之美

个人所得税

#include 
   
    using namespace std;int main(){
   	double n;	cin >> n;	n -= 60000;	if (n <= 0)cout << 0 << endl;	else if (n <= 36000)  cout << 0.03 * n << endl;	else if (n <= 144000) cout << 0.1 * n - 2520 << endl;	else if (n <= 300000) cout << 0.2 * n - 16920 << endl;	else if (n <= 420000) cout << 0.25 * n - 31920 << endl;	else if (n <= 660000) cout << 0.3 * n - 52920 << endl;	else if (n <= 960000) cout << 0.35 * n - 85920 << endl;	else cout << 0.45 * n - 181920 << endl;	return 0;}
   

Output:

一元二次方程

#include 
   
    #include 
    
     using namespace std;int main(){
   	double a, b, c;	cin >> a >> b >> c;	if (a == 0)	{
   		if (b == 0)		{
   			if (c == 0) cout << "无数组解" << endl;			else cout << "无解" << endl;		}		else cout << "x = " << -c / b << endl;	}	else	{
   		double delta = b * b - 4 * a * c;		if (delta < 0) cout << "无解" << endl;		else cout << "x1 = " << (-b + sqrt(delta)) / (2 * a) << ", x2 = " << (-b - sqrt(delta)) / (2 * a) << endl;	}	return 0;}
    
   

Output:

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